Shoto About to Get Real

[DarthScohin]

So I've finalized the design for my shoto...that is if you all think it'll work. (Ain't jumping the gun like last time )
SaberBuilder_render2.jpg

I'm going for the removable battery/sound pack that is on the YouTube channel since from my calculations the pommel (which has 1.36" IL) and the 4" connector which equals the 5" needed for the V6 Speaker mount will hold the pack.
My biggest question is will the short AV switch work with the 2" double female and a Cree LED work being so close (or perhaps I should go with a 3") ? Also what resistor will I need for the Royal Blue Cree-LED? the slotted middle isn't for a crystal chamber but a "fusion coil" window.

I think that's all my main questions right now, Thank You

PS: How does one work the LED AV switch on a NB (just solder it with the Cree-LED in circuit?)

[Silver Serpent]

It's gonna be a tight fit with that switch there. You'll need to use the v4 heat sink, or it won't fit at all.

http://forums.thecustomsabershop.com...e-to-Ohm-s-Law will teach you how to figure out your resistor value.

The accent LED in the switch can be wired parallel with the main blade, and it'll need its own resistor. The DynaOhm will do the job just fine, or you can calculate one yourself.

You say "shoto", but that saber is just shy of 11" long. It looks like a standard saber length to me. You can still put a short blade in it if you like though.

[DarthScohin]

Yeah I was going to do a 28" or 26" blade in it my other hilt is about 15" long so it'll feel and look shorter. I'll be sure to adjust my list accordingly thanks SS

[DarthScohin]

If the accent ring LED is connected in parallel with the blade the switch will ignite with the blade correct? Or will it be on when power is brought to the hilt?

[Forgetful Jedi Knight]

It will come on when the blade comes on.

[DarthScohin]

So if my calculations are correct I have a 3.7v battery and a Royal blue Cree meaning my resistor needs to be 3 ohms and 3W ?

3.7-2.7/1= 2.7 (3 Ohms)
2.7*1^2= 2.7 (3 Watts)

[Forgetful Jedi Knight]

So if my calculations are correct I have a 3.7v battery and a Royal blue Cree meaning my resistor needs to be 3 ohms and 3W ?

3.7-2.7/1= 2.7 (3 Ohms)
2.7*1^2= 2.7 (3 Watts)

Your Vf for the LED is wrong. That resistor is way too high.

[DarthScohin]

Oh I cant do math the other calculation I got was .29 ohms and 2.7 W

[Forgetful Jedi Knight]

Oh I cant do math the other calculation I got was .29 ohms and 2.7 W

You might want to try again.

[DarthScohin]

So I'm getting .29 and .29 which would mean 1 Ohm and 1 Watt is that right? Also I have the Trustfire 2400 going into this one that should be enough power right?