Hey guys, never tried running multiple LEDs off a single resistor, want to get some feedback before I do. I'm running the Tri-Rebel RRW with the two reds in parallel and the white FOC, on a NB2.0. Here's my calculations:

(3.7 - 2.3) / 0.7 = R = 2 ohm
(3.7 - 2.3) * 0.7 = P = 0.98 watts

So a 2 ohm/1 watt resistor for each LED. But I don't have one, so I'm trying to be a little creative. What if I wire up a single resistor for both parallel LEDs? Should be the same voltage, but twice the current:

(3.7 - 2.3) / 1.4 = R = 1 ohm
(3.7 - 2.3) * 1.4 = P = 1.96 watt

So a single 1 ohm/2 watt resistor should work, yes? I have plenty of those. I understand the risk of a single LED failing and then the other getting popped by the current, I'm okay with that. If one die were to fail, I would probably replace the LED or upgrade to the newest tech anyways. I just want to make sure my calculations are sound, and that I won't risk my NB2.0 in any way.

Thanks!
Tryp