battery issues

[djbordie]

yes but that will require a different resistor or a driver right?>

[Hasid Lafre]

No. Look at the resistor chart and see what one you need for 7.2V .

If you find the opposit plug the pack needs then then do everything like normal.

[djbordie]

ok im all good, im getting nimh or using some i have from my rc cars....
they are 1600 mah, 7.2v, is that ok?
i know MAh is the total capacity, so that shouldnt matter right?
the more MAH the better run time for the saber i guess right?

as long as its 7.2v with a proper resistor i should be rocking ya?

for a 5w cyan that is...

[Hasid Lafre]

Yes it should work. and yes the mor emah you have the more runtime you got.

The resistor needed for 7.2V is http://www.thecustomsabershop.com/pc...-resistor.aspx

[djbordie]

sweeet, this shall be done as soon as my order arrives cheers.

hopefully ultrasound will be ready soon, so my order does ship....

so its my fourth sabre, ill have lots of pics of them all up soon

[chase]

ok...well i have a 5v cyan and running it off a 9v battery...should i get the li-on charger to run the led better? would it make much difference if i dont have a driver? i plan on getting an ultra board...just not right away. if so.... could you direct me on knowing these things.

[djbordie]

you will just get longer run times with NiMh battery
as long as your using 9v either the little square battery or the 6xAA it will look the same, just last longer with the 6xAA and even longer with a high capacity 7.2v 1600mah or whatever lion or NiMh

[Novastar]

I hope this thread I created helps:

http://www.thecustomsabershop.com/fo...pic.php?t=2866

If not, all I can say is that a single AA has more energy density than a single 9v style battery.

In the end, this becomes important if you're trying to get super long run times. Driver boards will almost always do better than a resistor-only setup.

[traydemark]

I know this is (kind of) an old thread but I have a question about batteries and didn't want to make a new thread...

Ok... so I understand that when grouping batteries (of the same type), you just add voltages to get the overall voltage. But for mAh... how do you calculate that?

I'm planning on using Energizer (Industrial) C batteries because I have a box of them and they're 1.5v 8350 mAh. I'm assuming, you don't just add them because of some other stuff that happens in the background like self-discharging...I think...

[Hasid Lafre]

The mah of the batteries stay the same no matter how many you add up.

At least thats what I gather.