Help! Electricity Question - Battery and LED: Cree MC-E w/ 5V Power Bank

[fdesa12]

I'm intending to make a white blade using Cree MC-E using 4 LEDs wired in parallel, though this will be my first build. Will be buying a "cheap" empty of about 12" long.

First, some quick specs:
Cree MC-E LED (4-dice star) in cool white 6000K
@ 350mA, Vf = 3.2V, Luminous flux: 370 lm to 430 lm
Max current @ 700mA, Vf = 3.4V, Luminous flux: 160% increase (about 590 lm to 690 lm)

Li-ion battery:
Either 14500, 16850, or 26650.
Resistor needed per die at 400mA input: 2 ohm, >1W resistor per die
Total current draw ~ 1.6A
Total lumen output ~ up to 1780 lm.

So two things...
1) GOAL: Use a 5V 5000mAh power bank with a 1.5A output
Reason: I can solder a simple USB connector to connect the battery to; simple plug in/removal; cheap and multifunctional battery.
Problem: the 1.5A output... Do I need resistors???

I know batteries don't usually output a specific current and that it's usually the devices that draw it out instead... But since this powerbank has an output value in the specs and manual, I'm wondering if that actually means the output is controlled where I don't need resistors. After all, the current gets split up between the dice when everything is wired in parallel, right? That would give about 375mA per die.

2) Is ~1700 lumens too hot? I've never worked with a high-output light like this before so I don't have anything to compare with.
If this is too hot, what would be acceptable and safe?

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Edit: Correct me if I'm wrong but I might have just realized that if the 1.5A output of the battery exceeds what the LEDs are trying to draw, then the appropriate resistor for 5V battery should work just fine as it will resist the excess current. So if I use only 2 dice instead of 4 and intend to run it with a 400mA draw, this resistor per die should be fine.

So if I only use 2 dice w/ 2ohm resistor...
Total current drawn from battery = 900mA
Luminous Flux is about 1000 lm
Can anyone verify if my thoughts/calculations are correct?