like FJK said its not ideal but most definitely will work and give you a good looking saber but if you wanted ideal-ish the formula is R=(Vs-Vf)/I. Which for the xpe2 blues is forward voltage is 3.47v @1A so R=(3.7-3.47)/1=0.23 and wattage of .25w but since those are not readily available you would got to the next higher available resistor like the .47 ohm .5watt resistor in the store. whites are (3.7-3.15)/1=.55ohm. Now reason I say ideal-ish is because your battery drains so your source voltage will go down making the resistor to big (marginally) and also when fresh off the charger your voltage is actually closer to 4.2v making your value for your resistor slightly small. So if you want ideal you need a board that has current regulation like a PC or CF with CEX for a truly ideal driven LED and will give your LED the exact current you want it to get. Also I wouldn't drive your LED at 1.5A the added brightness you get is minimal at best and you are just reducing battery run time and life of the LED which should last a very very long time. Also with all dies on and running at 1.5A thats a total of 4.5A and a lot of batteries can have a hard time delivering that and also can make the board do weird things if it can't supply the amperage.
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