I've purchased a Cree Tri-XP-E2 with amber/amber/white diodes. From the specs in the shop, one of the amber diodes should have a forward voltage of 2.65V at 1000mA, and the white diode has 3.15V at 1000mA.
Using these specs and the 3.7V, 3400mAh Li-ion battery, I deduced the resistor value to be 1.5 Ohms. The power was calculated at 0.735W rounded up is 1 Watt.
Vf battery = 3.7V;
Vf LED Amber = 2.65V;
Vf LED White = 3.15V;
Ia = 700mA (since Red-Orange is 700mA, and they are close in the color spectrum)
Iw = 1000mA (correct or should I use the 700mA as well?)
R = (3.7V - 2.65V)/.7A
R = 1.5 Ohms (round up to 2 Ohms?)
P = 1.5(.7A)^2
P = 0.735W (round up to 1W) (R = 2 Ohms gives 0.98W)
Since there is a 2 Ohm/1 Watt resistor in the shop, I assume this is an accurate calculation.
However, the white diode presents me with a problem. my calculations yield a 1 Ohm 1 Watt resistor:
R = (3.7V - 3.15V)/1A
R = 0.6 Ohms (rounded to 1 Ohm)
P = 0.6(1A)^2
P = 0.6 W (rounded to 1 Ohm)
I don't see a resistor with this value, so I'm wondering if I should use a 2 Ohm 1 Watt for all three diodes since it works for the amber diodes?
If you see anything wrong with my calculations please let me know.
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