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Thread: Tri-Cree Continuity

  1. #11

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    It wasn't too hot. The iron was touching the board for too long a time. It was touching for too long a time because the iron wasn't hot enough to melt the solder quickly.

    The goal is to ZAP the solder quickly. Higher wattage, temperature control, electrostatic discharge protection are signs of a quality iron. An iron with low wattage, no temperature control, no ESD protection are signs of an inferior iron. Quality irons zap the solder quickly. Inferior irons do not.

  2. #12

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    Yep, it's a little counterintuitive at first. To avoid burning parts, you need a HOTTER iron.
    We all have to start somewhere. The journey is all the more impressive by our humble beginnings.

    http://led.linear1.org/1led.wiz for the lazy man's resistor calculator!
    http://forums.thecustomsabershop.com...e-to-Ohm-s-Law for getting resistor values the right way!

  3. #13

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    I can assure you the iron I used has ESD protection. I'm just a boob when it comes to soldering.

  4. #14

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    Before you start working on an expensive soundboard, practice on a old motherboard.

  5. #15

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    would the tri rebel and tri cree led's be any different in terms of how much voltage they need?

  6. #16

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    Each color is different as far as what voltage "it needs." However for everything sold here, a 3.7V lithium ion battery will power any individual LED die regardless of manufacturer, Rebel or Cree. You just need to resistor them as needed and wire the LEDs in parallel. This will cut into the battery's run-time though.

    You can start wiring LEDs in series when you bump up to a 7.4V battery, which will extend battery run-time but take up a lot more internal space. Again, this is regardless of manufacturer.

    To bottom line it, you need to look at the LED dies individually and what its forward voltage is. That forward voltage needs to be LESS than the battery's voltage. If you want to extend battery run-time by wiring LEDs in series, you need to add all of the forward voltages of the LEDs in question; that sum total needs to be LESS than the battery's voltage. Use Ohm's Law to calculate the resistor(s) needed.

  7. #17

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    thank you.

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