For my first build, I blindly followed diagrams found on these forums and managed to get a fully functional lightsaber!
However, I want to know what's going on so I've been reading up on Ohm's law and was wondering if my understanding is correct.
The scenario is, I have a Red/RoyalBlue/White Tri-Cree and want to mix the red and royal blue for a pinkish blade. With a NB, PeX, and 3.7v battery, the resistors are as follows:
Red- 2.59v run 1000mA
R = (3.7-2.59) / 1 = 1.11 which rounds up to 2
p = (1.11)*1^2 = 1.11 which rounds up to 2
Thus for the red die, I'd need a 2ohm 2W resistor
RoyalBlue- 3.41v run 1000mA
R = (3.7 - 3.41) / 1 = .29 which rounds up to 1
p = (.29)*1^2 = .29 which rounds up to 1
Thus for the royal blue die, I'd need a 1Ohm 1W resistor
White- 3.15v run 1000mA
R = (3.7-3.15) / 1 = 0.55 which rounds up to 1
p = (0.55)*1^2 = 0.55 which rounds up to 1
Thus for the resistor on the white, I'd need a 1Ohm 1W
Is my understanding correct?
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