From the item description in the store:
DPDT Latching green ring Illuminated switch.
There is no internal resistor on these so you need to use the correct resistor in order to not fry the LED.
The LED has a forward voltage of 3.3V and runs at 20mA. 4.8V would use a 82ohm 1/4 watt resistor, 6V would use a 150ohm 1/4 watt resistor. If you are not sure which to use please ask.
Ohms Law-- See this
Sticky elsewhere on the forum search is your friend : R = (V / I)
In your case R = ((3.7-3.3)/.020), R= ((.4)/.02), R = 20 Assuming this is wired directly to the battery as you haven't given any other information.
100 ohm will be too much resistance.
Someone please correct me if I am wrong.
Dodds
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