Page 2 of 2 FirstFirst 1 2
Results 11 to 17 of 17

Thread: LED Resistors and Ohm's Law

  1. #11

    Default

    you would have to come up with a compatible array of LEDs. If you wire them all in series, you can't deal with the forward voltage requirement.

    If you wire them all in parallel, you end up putting a resistor on each of them, or a very large resistor in front of them.

    If you create an array, mixing parallel and series, you can keep the forward voltage reqs down into manageable range, while reducing the # and wattage of resistors necessary to protect them from over current.

    If you google for LED parallel/series calculator, there is one I have used that will take the info about your LEDs, your power source, how many of them you have and create a workable array for you.

    AK-47s and Lightsabers, both so fun to build

  2. #12

    Default

    so if I want to wire up let say six of these
    http://www.radioshack.com/product/in...ductId=3097460
    using 3 AA
    this is how I would want to wire it up?

    Then I would just place a mom switch on the battery neg wire.
    after looking at the radio shack website it looks like they dont have exactly what the calculator recomended.
    It suggested.
    1/4 w
    56 ohm

    the closest I could find was
    1/2 w 47 ohm. so it looks like they will be overdriven. a little.
    Attached Images Attached Images
    Last edited by morpheus1977; 08-26-2010 at 11:38 AM.

  3. #13

    Default

    Doesn't Makoto just wire his all in series? The voltage stays the same, but the mA stacks per LED.

    For instance, you have 10x 3V 20mA LEDs which requires 3V 200mA to power them sufficiently.

  4. #14
    Council Member
    Jedi Council Member
    Rhyen Skytracker's Avatar
    Join Date
    Feb 2009
    Location
    Covington, GA
    Posts
    2,550

    Default

    In series the voltage will split and the current stay the same, it is parallel where the current will split and the voltage stay the same.

    Morph,
    You can use down to a 25 ohm resistor. Those LEDs have a max recommended voltage of 4 V so:

    (4.5V source - 4 V forward) / .02A = 25 ohm resistor.
    Last edited by Rhyen Skytracker; 08-26-2010 at 12:40 PM.

    Live long and...I mean May the force be with you. http://saberconcepts.50.forumer.com/index.php

  5. #15

    Default

    Thanks Rhyen
    the lowest I could find is 33 so I will use that. I want these nice and bright. I will be using diffusers with them.

    But this is going to be ugly wired up.(yea it will be in the lancer but still ugly)

    quick question instead of having to buy a three AA battery pack. I still have the battery sled from my MR Vader saber can I use that?
    Last edited by morpheus1977; 08-26-2010 at 12:54 PM.

  6. #16
    Council Member
    Jedi Council Member
    Rhyen Skytracker's Avatar
    Join Date
    Feb 2009
    Location
    Covington, GA
    Posts
    2,550

    Default

    Yes, you can use it if it will fit.

    Live long and...I mean May the force be with you. http://saberconcepts.50.forumer.com/index.php

  7. #17

    Default

    ok got it can somebody tell me which is pos and which is neg?

    *edit* never mind figured it out LOL
    Last edited by morpheus1977; 08-26-2010 at 09:08 PM.

Bookmarks

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •