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Type: Posts; User: MythranDir

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  1. Replies
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    One thing to look out for is the amount of...

    One thing to look out for is the amount of current that can be drawn from a 9 V is low compared to what can be obtained from an AA. The following link compares the current sourcing capacity of...
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    This is probably a bit of overkill, but I used a...

    This is probably a bit of overkill, but I used a small drill and made two holes on either side of the pin. Then, I used some needle nose pliers and it pulled out quite easily.

    MythranDir
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    Tim, I see you had one of your converted Luke...

    Tim, I see you had one of your converted Luke sabers on ebay, but I was out bid!! Will you be putting anymore converted Luke's (or other models) on ebay??

    MythranDir
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    I agree with you!! It looks great no matter what...

    I agree with you!! It looks great no matter what the multimeter says. I am just going to accept what the MR board can deliver.

    MythranDir
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    Ok, ignore what I said in my previous post. The...

    Ok, ignore what I said in my previous post. The new batteries I bought crapped out after 30 minutes of testing. Geez. I am about out of ideas. It seems the best configuration is 4 batteries, period....
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    I found a way to get more current using the MR...

    I found a way to get more current using the MR board. I use 2 Energizer 1.5 volt AA batteries, and one 3.6 V lithium battery. I found this battery at a speciality store, and it cost $10! This...
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    I think your measurements are ok. If your...

    I think your measurements are ok. If your question is why does the current go down to 450 mA when the LED is in the circuit, the reason is there is a ~ 3.9 V drop across the LED, which means the...
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    Tim, You can measure the current when the LED...

    Tim,

    You can measure the current when the LED is in the circuit. The multimeter is put into the circuit in series with the LED. In this way, you will be able to tell what the current actually is...
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    Tim, for a given desired current, the required...

    Tim, for a given desired current, the required value of resistance is obtained by dividing the voltage difference between the battery and diode by the desired current. For example, for a battery...
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    Luke ROTJ 05 Conversion

    Tim,

    I am a big fan of the Luke ROTJ saber, which I picked up a few weeks ago. I don't suppose you have any plans on offering a conversion kit for this saber? As with the Mace Windu, it would...
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    Thanks for the info!! I will definitely give this...

    Thanks for the info!! I will definitely give this a try.

    MythranDir
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    Tim, It looks beautiful! I think I will do the...

    Tim,

    It looks beautiful! I think I will do the same comparison you did (4 AA's with a resistor vs. 3 AA's using the MR board) and repeat my current measurements.



    MythranDir
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    Tim, I have a few more thoughts about the...

    Tim,

    I have a few more thoughts about the issue of current and brightness.

    First, the amber and red Luxeons operate at a forward voltage of ~2.95 V compared to the green and blue LED's that...
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    I have noticed the same power problem. When I...

    I have noticed the same power problem. When I hook up a Lux III to the MR board I barely get 250 mA (this was a Blue LED)!! Other people have resorted to wiring the LED directly to the battery...
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