Hi, all.

I'm hoping someone can verify that I've got the right wiring schematic here.

All I'm trying to do is replace a busted AAA battery pack with 1, an 18650 and 2, a recharge port.

tcss-us-rewiring.jpg

Actually, typing out this post makes me realize: I may not have a buckpuck, I may have a resistor, so then do I need to add in a new resistor? I'm doing this on a US saber, and https://www.thecustomsabershop.com/C...LED-P1035.aspx says for the green tri-cree, it has a forward voltage @ 1000mA of 3.7V.

4x AAA -> 18650 conversion:

4 AAA in series will be 6V

18650 is 4.2V

So then consulting http://forums.thecustomsabershop.com...e-to-Ohm-s-Law :

AAA build:

R = ( 6 - 3.7 ) / 1 = 2.3 ohm

P = R * I^2 = 2.3 * 1^2 = 2.3 W, so I probably have a 2 ohm, 2 watt resistor already in there.

What I'll need is:

R = ( 4.2 - 3.7 ) / 1 = 0.5 ohm

P = 0.5 * 1^2 = 0.5 W, so I'll need to rip out my current resistor and replace it with a 0.5 ohm, 0.5 watt resistor.

**So then my questions are:**

1, is my wiring diagram at the top correct?

2, are my calculations correct? I have other sabers I need to repair, so I want to make sure my process is correct for (say) a 3.4V LED.

3, since the 18650 is 3.7V and the green LED is run at 3.7V, can I skip a resistor entirely, or do I still want a tiny resistor?

4, someday I want to also convert my 2x 14500s setups into using 18650s as well. My thinking is that I just have to make sure I'm buying 7.4V 18650s, and I just replace them without any other mods (I'm pretty sure my Li-ion sabers have buckpucks). Is that correct?

Thanks in advance for any help!

I'm hoping someone can verify that I've got the right wiring schematic here.

All I'm trying to do is replace a busted AAA battery pack with 1, an 18650 and 2, a recharge port.

tcss-us-rewiring.jpg

Actually, typing out this post makes me realize: I may not have a buckpuck, I may have a resistor, so then do I need to add in a new resistor? I'm doing this on a US saber, and https://www.thecustomsabershop.com/C...LED-P1035.aspx says for the green tri-cree, it has a forward voltage @ 1000mA of 3.7V.

4x AAA -> 18650 conversion:

4 AAA in series will be 6V

18650 is 4.2V

So then consulting http://forums.thecustomsabershop.com...e-to-Ohm-s-Law :

AAA build:

R = ( 6 - 3.7 ) / 1 = 2.3 ohm

P = R * I^2 = 2.3 * 1^2 = 2.3 W, so I probably have a 2 ohm, 2 watt resistor already in there.

What I'll need is:

R = ( 4.2 - 3.7 ) / 1 = 0.5 ohm

P = 0.5 * 1^2 = 0.5 W, so I'll need to rip out my current resistor and replace it with a 0.5 ohm, 0.5 watt resistor.

1, is my wiring diagram at the top correct?

2, are my calculations correct? I have other sabers I need to repair, so I want to make sure my process is correct for (say) a 3.4V LED.

3, since the 18650 is 3.7V and the green LED is run at 3.7V, can I skip a resistor entirely, or do I still want a tiny resistor?

4, someday I want to also convert my 2x 14500s setups into using 18650s as well. My thinking is that I just have to make sure I'm buying 7.4V 18650s, and I just replace them without any other mods (I'm pretty sure my Li-ion sabers have buckpucks). Is that correct?

Thanks in advance for any help!